Chemistry II For Dummies (For Dummies (Math & Science)) by Moore
Author:Moore
Language: eng
Format: mobi
Publisher: John Wiley and Sons
Published: 2012-06-08T04:00:00+00:00
0.500 M – x x x
The ionization of cyanic acid is an equilibrium and has an associated Ka. Notice that the cyanate ion, OCN-, appears in both equations. The presence of the weak acid (cyanic acid) indicates that this a Ka problem.
2. Find the Ka value.
You can get it from the pKa.
Ka = = 10-3.46 = 3.5 x 10-4
3. Write the Ka expression.
4. Show both sources of the cyanate ion in the equilibrium constant expression.
This problem has two sources of the cyanate ion. You get 0.750 M from the dissociation of the sodium cyanate and x amount from the ionization of the cyanic acid.
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